Integral Tentu dari soal digambar adalah
Jawab:
[tex]\frac{58}{3}[/tex] atau 19,33..
Penjelasan dengan langkah-langkah:
[tex]\int\limits^3_1 {(2x^{2} +x-1)} \, dx[/tex]
cari F(x) terlebih dahulu:
F(x) = [tex]\frac{2}{3}x^{3} + \frac{1 }{2} x^{2}-x+C[/tex] = [tex]\frac{x(4x^{2} +3x-6)}{6}[/tex]
Rumus:
[tex]\int\limits^a_b {f(x)} \, dx = F(b) -F(a)[/tex]
maka,
[tex]\int\limits^3_1 {(2x^{2} +x-1)} \, dx = (\frac{3(36 +9-6)}{6}) - (\frac{4 +3-6}{6})[/tex]
= [tex]\frac{117}{6} - \frac{1}{6}[/tex] = [tex]\frac{116}{6}[/tex] = [tex]\frac{58}{3}[/tex] = 19,33..
Semoga membantu! Apresiasi kalian sangat berharga untuk saya :)
Feel free to ask if there's something you don't understand from my explanation :)
